12x^2-50x+50=0

Solution for 12x^2-50x+50=0 equation:

12x^2-50x+50=0

a = 12; b = -50; c = +50;
Δ = b2-4ac
Δ = -502-4·12·50
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10}{2*12}=\frac{40}{24}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10}{2*12}=\frac{60}{24}
=2+1/2
$